A boy is walking away from a well at a speed of `1.0 m//s` in a direction at right angles to the wall. As he walks, he below a whistle steadily. An observer towards whom the boy is walking hears `4.0` beats per second. If the speed of sound is `340 m//s` , what is the frequency of the whistle?
A. 480 Hz
B. 680 Hz
C. 840 Hz
D. 1000 Hz
A. 480 Hz
B. 680 Hz
C. 840 Hz
D. 1000 Hz
Correct Answer – B
The frequency of direct sound of whistle heard by observer is
`n_1=(v)/(v-v_S)n=(340)/(340-1)xxn=(340)/(339)n` ..(i)
Frequency of sound of whistle reflected by wall is
`n_2=(v)/(v+v_S)n=(340)/(341)n` .(ii)
Given, `n_1-n_2=4`
Therefore, `(340)/(339)n-(340)/(341)n=4`
`impliesn=680Hz`