A boy after swimming comes out from a pool covered with a film of water weighing 80 g .How much heat must be supplied to evaporate this water ? `(Delta_(v) H^(@)=40.79 kJmol^(-1))`
A. `1.61 xx10^(2) kJ`
B. `1.71 xx 10^(2)kJ`
C. ` 1.81xx10^(2) kJ `
D. ` 1.91 xx 10^(2) kJ `
A. `1.61 xx10^(2) kJ`
B. `1.71 xx 10^(2)kJ`
C. ` 1.81xx10^(2) kJ `
D. ` 1.91 xx 10^(2) kJ `
Correct Answer – C
Given `: Delta_(“vap”) H^(@) `for`H_(2)O= 40.79 kJ mol^(-1)`
Water to be evaporated `= 80 g ( 80)/( 18) mole`
`=4.44` mole
Heat required for evaporated of 1 moleof `H_(2)O =40.79kJ`
`:. `Heat required for evaporated of 4.44 moleof`H_(2)O=40.79 xx 4.44 = 1.81 xx 10^(2) kJ`