A bar of iron is 10 cm at `20^(@)C`. At `19^(@)C` it will be `(alpha_(Fe)=11xx10^(-6)//.^(@)C)`
A. `11xx10^(-6)`cm longer
B. `11xx10^(-6)cm` cm shorter
C. `11xx10^(-5)cm` shorter
D. `11xx10^(-5)cm` longer
A. `11xx10^(-6)`cm longer
B. `11xx10^(-6)cm` cm shorter
C. `11xx10^(-5)cm` shorter
D. `11xx10^(-5)cm` longer
Correct Answer – C