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Falguni Raja
Asked: 2022-11-10T22:17:48+05:30 In:

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by
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  1. `KE = (1)/(2) mv^(2) = W_(“friction”) + (1)/(2) Kx^(2)`
    `rArr (1)/(2) xx 2xx 4^(2) = 15 x + (1)/(2) xx 10000 xx x^(2)`
    `rArr 5000 x^(2) + 15 x – 16 = 0`
    `rArr x = 0.055 m` or `x = 5.5 cm`.

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Charandeep Lal Parsa
Asked: 2022-11-02T11:40:47+05:30 In:

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by
A. 5.5 cm
B. 2.5 cm
C. 11.0 cm
D. 8.5 cm

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by
A. 5.5 cm
B. 2.5 cm
C. 11.0 cm
D. 8.5 cm
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  1. Correct Answer – C
    `(1)/(2)mv^2=(1)/(2)kx^2+W_f`
    `(1)/(2)(2)(4)^2=(1)/(2)(10000)x^2+f_(k)x`
    `16=5xx10^3x^3+15x`
    `5xx10^3x^3+15x-16=0`
    `x=(-15+-sqrt((15)^2+4xx5xx10^2xx16))/(5xx10^3)`
    `=(11)/(100)m=11cm`

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Ajinkya Bali
Asked: 2022-11-01T16:51:53+05:30 In:

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by
A. `2.5`
B. `11.0`
C. `8.5`
D. `5.5`

A `2kg` block slides on a horizontal floor with the a speed of `4m//s` it strikes a uncompressed spring , and compresses it till the block is motionless . The kinetic friction force is compresses is `15 N` and spring constant is `10000 N//m` . The spring by
A. `2.5`
B. `11.0`
C. `8.5`
D. `5.5`
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  1. Correct Answer – D
    Let the spring be compressed by `x`.
    Loss in `KE` of block
    = Gain in `PE` of spring + Work done against friction
    `rArr (1)/(2) xx 2 xx4^(2) =(1)/(2) 1000 x^(2) + 15 x`
    On solving, we get `x = 5.5 cm`.

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