4/3cot square 30°+3sin square 60°-2cosec square 60°-3/4tan square 30°.
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{tex}\\begin{array}{l}\\frac43cot^2\\;30\\;+3\\;\\sin^{2\\;}60\\;-\\;2\\cos ec^{2\\;}60\\;-\\frac34\\tan^{2\\;}30\\\\Putting\\;the\\;values\\;of\\;\\sin\\;60,\\;cot\\;30,\\;\\cos ec\\;60\\;\\tan\\;30\\;we\\;get\\\\=\\frac{4\\;}{3\\;}(\\sqrt{3)}^2\\;+\\;3\\;(\\;\\frac{\\sqrt3}2)^2\\;-\\;2\\;(\\frac2{\\sqrt3})^2\\;-\\;\\frac34(\\frac1{\\sqrt3})^2\\\\=\\;4\\;+\\frac94\\;-\\;\\frac83\\;-\\;\\frac14\\;\\\\=\\;4+\\;2\\;-\\frac83\\\\=\\;6\\;-\\frac83\\\\=\\;\\frac{(18-8)}3\\\\=\\;\\frac{10}3\\end{array}{/tex}