10 mL of `N//20 NaOH` solution is mixed with 20 mL of `N//20 HCI` solution. The resulting solution will :
A. `40mL`
B. `20mL`
C. `30mL`
D. `5mL`
A. `40mL`
B. `20mL`
C. `30mL`
D. `5mL`
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Correct Answer – A
`HCl +AgNO_(3) rarr AgCl +HNO_(3)`
m equivalents of `HCl` left `=0.5`
m. equivalents of `HNO_(3)` formed `= 1.5`
`V_(a) N_(a) = V_(b)N_(b), 2 = V_(b) xx 0.05`
Volume of `NaOH = 40ml`