0.1 g of metal combines with 46.6 mL of oxygen at STP. The equivalent weight of metal is
A. 12
B. 24
C. 18
D. 36
A. 12
B. 24
C. 18
D. 36
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a) 1 mole of `O_(2)` = 4 equivalent of oxygen
22400 mL of `O_(2)` = 4 equivalent of oxygen
46.6 mL of `O_(2)` = (4/22400) xx 46.6 = 0.00832 eq.
Equivalent of metal = Equivalent of oxygen
(Weight)/(Equivalent) = 0.00832
0.1/E = 0.00832 `rARr` E= (0.1)/(0.00832) = 12.0