If marks of A is 20% more than that of B. Then, marks of B is how much percent less that of A.
1. 34.56%
2. 17.86%
3. 17.89%
4. 16.66%
1. 34.56%
2. 17.86%
3. 17.89%
4. 16.66%
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Correct Answer – Option 4 : 16.66%
Given:
Marks of A = Marks of B + 20% marks of B
Calculation:
Let the B’s marks is x
A’s marks = 20% of x + x
⇒ 120x/100
Required percentage = {[(120x/100) – x]/[115x/100]} × 100
⇒ {[(20x/100)]/[(120x/100)]} × 100
⇒ 16.66%
Alternate method:
If A is x% more than B, then B is {[(x)/(100 + x)] × 100}% less than A.
⇒ [(20/120) × 100]%
⇒ 16.66%