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  1. Asked: 3 years agoIn: Nsep

    A large cylindrical vessel contains water to a height of 10 m. It is found that the thrust acting on the curved surface is equal to that at the bottom. If atmospheric pressure can support a water column of 10 m, the radius of the vessel is

    (a) 10 m (b) 15 m (c) 5 m (d) 25 m 

    cb469
    Added an answer about 3 years ago

    Correct option (b)  15 mExplanation:Thrust on the curved surface 2πRh (P0 + h/2) = 300πR  here as the thrust on the bottom = πR2h(P0 + h/2) = 20πR2. The atmospheric pressure in terms of column of water is 10 m. equating the two thrusts gives R = 15 m

    Correct option (b)  15 m

    Explanation:

    Thrust on the curved surface 2πRh (P0 + h/2) = 300πR  here as the thrust on the bottom = πR2h(P0 + h/2) = 20πR2. The atmospheric pressure in terms of column of water is 10 m. equating the two thrusts gives R = 15 m

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  2. Asked: 3 years agoIn: Nsep

    Consider two point masses m1 and m2 connected by alight rigid rod of length r0. The moment of inertia of the system about an axis passing through their centre of mass and perpendicular to the rigid rod is given by

    5dcaf
    Added an answer about 3 years ago

    Correct option  (B) ur02

    Correct option  (B) 

    ur02

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  3. Asked: 3 years agoIn: Nsep

    An isolated metallic object is charged in vacuum to a potential V0 using a suitable source, its electrostatic energy being W0. It is then disconnected from the source and immersed in a large volume of dielectric with dielectric constant K. The electrostatic energy of the sphere in the dielectric is :

    (A)  K2W0

    (B)   K W0

    (C)   W0/K2

    (D)  W0/K

    05049
    Added an answer about 3 years ago

    Correct option  (D)  W0/KExplanation:U =  Q2 /2C since C will become k timesSo U will become 1/k times 

    Correct option  (D)  W0/K

    Explanation:

    U =  Q2 /2C since C will become k times

    So U will become 1/k times 

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  4. Asked: 3 years agoIn: Nsep

    A ball is dropped onto a horizontal surface from a height of 36 cm. After bouncing several times it comes to rest covering a total distance of 100 cm measured in a vertical direction. The percentage loss in its kinetic energy after its first impact is

    (a) 36 (b) 64 (c) 53 (d) 96 

    f0022
    Added an answer about 3 years ago

    Correct option  (c)  53Explanation:One can write the series 100 = 36 + 2 x 36 (e2 + e4 + e6 + ..) giving  e2 = 8/17 where e is the coefficient of restitution. Now, the percentage loss of kinetic energy = change in kinetic energy/original kinetic energy x 100. Note that the speed after impact is e tiRead more

    Correct option  (c)  53

    Explanation:

    One can write the series 100 = 36 + 2 x 36 (e2 + e4 + e6 + ..) giving  e2 = 8/17 where e is the coefficient of restitution. Now, the percentage loss of kinetic energy = change in kinetic energy/original kinetic energy x 100. Note that the speed after impact is e times the initial speed. This gives the percentage loss as 52.94 which is almost 53 %.

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  5. Asked: 3 years agoIn: Nsep

    It is required to decide the ratio (e1 / e2) by sum and difference method also. Four cells with different values of emf E are available. One must use a cell of emf E equal to 

    (a) 1.40 V  (b) 2.0 V  (c) 4.5 V  (d) 1.08 V 

    5fbca
    Added an answer about 3 years ago

    Correct option  (c) 4.5 VExplanation:Ratio of emfs :  e1/e2  = l1/l2   Ratio of emfs by sum and difference method : e1 + e2/e1 - e2 =  l1/l2 = e1/e2  = l1 + l2 /l1 - l2  The emf of the cell used in the primary circuit should be greater than (e1 + e2) E > (1.4 + 1.08)E > 2.48 volt

    Correct option  (c) 4.5 V

    Explanation:

    Ratio of emfs :  e1/e2  = l1/l2   

    Ratio of emfs by sum and difference method : e1 + e2/e1 – e2 =  l1/l2 = e1/e2  = l1 + l2 /l1 – l2  

    The emf of the cell used in the primary circuit should be greater than (e1 + e2) E > (1.4 + 1.08)

    E > 2.48 volt

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  6. Asked: 3 years agoIn: Nsep

    Refer to the circuit given below. Output voltage V0 is measured between points a and b. Then,

    (a)  the peak value of V0 is 2.5 V above the minimum if the diode is assumed to be ideal 

    (b)  the positive half cycle of the input is clipped 

    (c)  the circuit acts as a rectifier 

    (d)  the peak value V0 is about 3.2 V above the minimum if D is silicon diode (non-ideal)

    ce9dc
    Added an answer about 3 years ago

    Correct option   (a) the peak value of V0 is 2.5 V above the minimum if the diode is assumed to be ideal  (c) the circuit acts as a rectifier (d) the peak value V0 is about 3.2 V above the minimum if D is silicon diode (non-ideal)Explanation:The diode is reverse biased in the +ve half cycle.The diodRead more

    Correct option   (a) the peak value of V0 is 2.5 V above the minimum if the diode is assumed to be ideal  (c) the circuit acts as a rectifier (d) the peak value V0 is about 3.2 V above the minimum if D is silicon diode (non-ideal)

    Explanation:

    The diode is reverse biased in the +ve half cycle.

    The diode is forward biased in the –ve half cycle. 

    (a)  If the diode is ideal, if offers infinite resistance in reverse bias, thus the entire input appears across the output. (2.5 V above the minimum) 

    (c)  Since the negative half cycle is clipped, the circuit acts as rectifier. 

    (d)  For a non-ideal silicon diode, threshold voltage is 0.7 V, so the output voltage will be (0.7 + 2.5 = 3.2 V) above the minimum.

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  7. Asked: 3 years agoIn: Nsep

    A thin annular metal disc of inner and outer radii R1 and R2  respectively, is freely suspended from a point on its outer circumference. The length of the corresponding equivalent simple pendulum is

    6207e
    Added an answer about 3 years ago

    Correct option  (b)Explanation:Moment of inertia of annular disc about the axis under consideration can be written as m/2(R21 + R22) + mR22 Comparing the expression for the periodic time of this oscillating disc as a compound pendulum with that of a simple pendulum, we get the equivalent length. 

    Correct option  (b)

    Explanation:

    Moment of inertia of annular disc about the axis under consideration can be written as m/2(R21 + R22) + mR22 Comparing the expression for the periodic time of this oscillating disc as a compound pendulum with that of a simple pendulum, we get the equivalent length. 

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  8. Asked: 3 years agoIn: Nsep

    The best material for strips marked S and S1 is

    (a) Plastic (b) Aluminium (c) Cast Iron (d) Plated Brass

    1ac07
    Added an answer about 3 years ago

    Correct option  (d) Plated BrasExplanation:Brass is the best conducting material out of the available options. As it offers minimum resistance, the readings will be close to actual values.

    Correct option  (d) Plated Bras

    Explanation:

    Brass is the best conducting material out of the available options. As it offers minimum resistance, the readings will be close to actual values.

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  9. Asked: 3 years agoIn: Nsep

    If the threshold of hearing is assumed to be the reference (0 dB), then the threshold of pain is taken to be 120 dB. Let the corresponding sound intensities be I0 and I respectively. Then I0/I is

    (a) 120 (b) 1012 (c) 10-12 (d) 101.2 

    82fad
    Added an answer about 3 years ago

    Correct option (C) 10-12Explanation:Use the definition of dB scale: 120 = 10 log10 (I/I0) , which gives  (I0/I)    = 10-12 .

    Correct option (C) 10-12

    Explanation:

    Use the definition of dB scale: 120 = 10 log10 (I/I0) , which gives  (I0/I)    = 10-12 .

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  10. Asked: 3 years agoIn: Nsep

    The variation of amplitude A with respect to time t is shown as

    b4d1f
    Added an answer about 3 years ago

    Correct option  (b)Explanation:Ideal case: no damping: the amplitude remains constant. (third graph)Practical case: damping is present: amplitude decreases exponentially. Assuming the damping force is directly proportional to velocity of the bob. We can write the amplitude : A = A0 e- bt/2m Here b iRead more

    Correct option  (b)

    Explanation:

    Ideal case: no damping: the amplitude remains constant. (third graph)

    Practical case: damping is present: amplitude decreases exponentially. Assuming the damping force is directly proportional to velocity of the bob. We can write the amplitude : A = A0 e- bt/2m

     Here b is damping constant and m is mass of the pendulum bob.

    So the correct option is (b) 

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