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  1. Asked: 3 years agoIn: Motion

    The area under the velocity-time graph is equal to the:

    A. speed of the body 

    B. distance travelled by the body 

    C. magnitude of the displacement of the body 

    D. none of these

    f3f31
    Added an answer about 3 years ago

    We know that, Displacement = Velocity × Time So, the area under the curve of Velocity – Time graph of a body will give the magnitude of displacement of the body. Hence option C is correct.

    We know that, 

    Displacement = Velocity × Time 

    So, the area under the curve of Velocity – Time graph of a body will give the magnitude of displacement of the body. 

    Hence option C is correct.

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  2. Asked: 3 years agoIn: Motion

    What is the Difference between Speed and Velocity?

    1df1a
    Added an answer about 3 years ago

    VelocitySpeedVelocity can be defined as the rate at which an object changes position in a certain direction.The rate at which an object covers a certain distance is known as speed.Vector quantityScalar quantityVelocity can be zero, negative, or positive.Speed can never be negative or zero.The velociRead more

    Velocity Speed
    Velocity can be defined as the rate at which an object changes position in a certain direction. The rate at which an object covers a certain distance is known as speed.
    Vector quantity Scalar quantity
    Velocity can be zero, negative, or positive. Speed can never be negative or zero.
    The velocity of the object changes with the change in direction, therefore the object must follow one direction. The average speed will continue to count even if the object change direction.

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  3. Asked: 3 years agoIn: Motion

    A trolley, while going down an inclined plane, has an acceleration of 2 cm/s2 . What will be its velocity 3 s after the start?

    6ef3f
    Added an answer about 3 years ago

    Here we have, Initial velocity, u = 0 m/s Acceleration (a) = 2 cm/s2 = 0.02 m/s2 Time (t) = 3 s Final velocity, v = ? We know that, v = u + at Therefore, v = 0 + 0.02 × 3 m/s ⇒ v = 0.06 m/s Therefore the final velocity of trolley will be 0.06 m/s after start. 

    Here we have, 

    Initial velocity, u = 0 m/s 

    Acceleration (a) = 2 cm/s2 = 0.02 m/s2 

    Time (t) = 3 s 

    Final velocity, v = ? 

    We know that, v = u + at 

    Therefore, v = 0 + 0.02 × 3 m/s 

    ⇒ v = 0.06 m/s 

    Therefore the final velocity of trolley will be 0.06 m/s after start. 

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