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  1. Asked: 3 years agoIn: Kvpy

    Meiosis-I and meiosis-II are characterised by the separation of

    (a) homologous chromosomes; sister chromatids

    (b) sister chromatids; homologous chromosomes

    (c) centromere; telomere

    (d) telomere; centromere

    b6047
    Added an answer about 3 years ago

    Answer is : (a) homologous chromosomes; sister chromatidsMeiosis-I Reduction division (2n → n), separation of homologous chromosomes results in reduction of chromosome ploidy to half.Meiosis-II Similar to mitosis where sister chromatids separate.

    Answer is : (a) homologous chromosomes; sister chromatids

    Meiosis-I Reduction division (2n → n), separation of homologous chromosomes results in reduction of chromosome ploidy to half.

    Meiosis-II Similar to mitosis where sister chromatids separate.

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  2. Asked: 3 years agoIn: Kvpy

    Fruit and leaf drop at early stages can be prevented by the application of 

    (a) cytokinins 

    (b) ethylene 

    (c) auxins 

    (d) gibberellic acid

    e1b17
    Added an answer about 3 years ago

    Correct option is (c) auxinsAuxin delays abscission of leaves and fruits at early stages. Whenever leaf or fruit fall occurs, the organ concerned stops producing auxin. However, it promotes abscission of older, mature leaves and fruits.

    Correct option is (c) auxins

    Auxin delays abscission of leaves and fruits at early stages. Whenever leaf or fruit fall occurs, the organ concerned stops producing auxin. However, it promotes abscission of older, mature leaves and fruits.

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  3. Asked: 3 years agoIn: Kvpy

    Let S = {1, 2, 3, …., 40) and let A be a subset of S such that no two elements in A have their sum divisible by 5. What is the maximum number of elements possible in A?

    (a) 10

    (b) 13

    (c) 17

    (d) 20

    05d8c
    Added an answer about 3 years ago

    Answer is : (c) 17We have, S = {1, 2, 3, 4, ..., 40}A is subset of S whose sum of two element of A is not divisible by 5.Possible set A = {1, 2, 5, 6, 7, 11, 12, 16, 17, 21, 22, 26, 27, 31, 32, 36, 37}∴ Maximum number of elements in A is 17.

    Answer is : (c) 17

    We have, S = {1, 2, 3, 4, …, 40}

    A is subset of S whose sum of two element of A is not divisible by 5.

    Possible set A = {1, 2, 5, 6, 7, 11, 12, 16, 17, 21, 22, 26, 27, 31, 32, 36, 37}

    ∴ Maximum number of elements in A is 17.

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  4. Asked: 3 years agoIn: Kvpy

    A desert lizard (an ectotherm) and a mouse (an endotherm) are placed inside a chamber at 15ºC and their body temperature [T(L) for the lizard and T(M) for the mouse] and metabolic rates [M(L) for the lizard and M(M) for the mouse] are monitored. Which one of the following is correct –

    (A)  T(L) and M(L) will fall while T(M) and M(M) will increase

    (B)  T(L) and M(L) will increase while T(M) and M(M) will fall

    (C)  T(L) and M(L) will fall, T(M) will remain same and M(M) will increase

    (D)  T(L) and M(L) will remain same and T(M) and M(M) will decrease 

    f807b
    Added an answer about 3 years ago

    Correct option (C) T(L) and M(L) will fall, T(M) will remain same and M(M) will increase Explanation:Desert lizard is an ectotherm (poikilotherm) whose body temperature varies according to environmental temperature.So at 15ºC T(L) will fall due to fall in T(M)While mouse is an endotherm (Homeotherm)Read more

    Correct option (C) T(L) and M(L) will fall, T(M) will remain same and M(M) will increase 

    Explanation:

    Desert lizard is an ectotherm (poikilotherm) whose body temperature varies according to environmental temperature.

    So at 15ºC T(L) will fall due to fall in T(M)

    While mouse is an endotherm (Homeotherm) whose body temperature remains constant always due to variation is metabolic rate

    In homeotherms metabolic rate is inversely proportional to environmental temperature. So at 15ºC T(M) remain same and M((M) will increased.  

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  5. Asked: 3 years agoIn: Kvpy

    Methane is greenhouse gas because –

    (A)  it absorbs longer wavelengths of the electromagnetic spectrum while transmitting shorter wavelengths.

    (B) it absorbs shorter wavelengths of the electromagnetic spectrum while transmitting longer wavelengths

    (C) it absorbs all wavelengths of the electromagnetic spectrum

    (D) it transmits all wavelengths of the electromagnetic spectrum

    5c48f
    Added an answer about 3 years ago

    Correct option  (A) it absorbs longer wavelengths of the electromagnetic spectrum while transmitting shorter wavelengths.Explanation:Absorbs infrared radiation thus it absorbs longer wavelength of EM wave spectrum while transmitting shorter wavelength.

    Correct option  (A) it absorbs longer wavelengths of the electromagnetic spectrum while transmitting shorter wavelengths.

    Explanation:

    Absorbs infrared radiation thus it absorbs longer wavelength of EM wave spectrum while transmitting shorter wavelength.

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  6. Asked: 3 years agoIn: Kvpy

    The intensity of sound during the festival season increased by 100 times. This could imply a decibel level rise from – 

    (A)  20 to 120 dB

    (B)  70 to 72 dB

    (C)  100 to 10000 dB

    (D)  80 to 100 dB 

    1c3b9
    Added an answer about 3 years ago

    Correct option  (D) 80 to 100 dBExplanation:Loudness of sound in decibel dB = 10 log10 (I/I0)when intensity of sound become 100 I then new decibel level = dB' = 10 log10 (100I/I0)dB' – dB = 10 log 10 100 dB' – dB = 20∴ decibel rise by 20 dB only one option i.e. 80 to 100 dB match with it

    Correct option  (D) 80 to 100 dB

    Explanation:

    Loudness of sound in decibel dB = 10 log10 (I/I0)

    when intensity of sound become 100 I then new decibel level = dB’ = 10 log10 (100I/I0)

    dB’ – dB = 10 log 10 100 

    dB’ – dB = 20

    ∴ decibel rise by 20 dB 

    only one option i.e. 80 to 100 dB match with it

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  7. Asked: 3 years agoIn: Kvpy

    Codon degeneracy means that

    (a) several amino acids are coded by more than one codon

    (b) one codon can code for many amino acids

    (c) one amino acid can be coded by only one codon

    (d) the codons are triplet nucleotide sequences

    d9090
    Added an answer about 3 years ago

    Answer is : (a) several amino acids are coded by more than one codonThere are 64 codons present in each living organism, out of which, 61 codons represent or code for amino acids and rest three are stop codons. Thus, there are more codon combinations than there are amino acids. The genetic code is dRead more

    Answer is : (a) several amino acids are coded by more than one codon

    There are 64 codons present in each living organism, out of which, 61 codons represent or code for amino acids and rest three are stop codons. Thus, there are more codon combinations than there are amino acids. The genetic code is described as degenerate because more than one codon sequence can code for the same amino acid.

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  8. Asked: 3 years agoIn: Kvpy

    A pathogen which cannot be cultured in an artificial medium is

    (a) protozoan

    (b) virus

    (c) bacterium

    (d) fungus

    bd97a
    Added an answer about 3 years ago

    Answer is : (b) virusVirus cannot be cultured in an artificial medium. It multiples only in living cells. Viruses are obligate intracellular parasites.They lack metabolic machinery to generate energy or to synthesise proteins, instead they rely on their host cells to carry out these functions

    Answer is : (b) virus

    Virus cannot be cultured in an artificial medium. It multiples only in living cells. Viruses are obligate intracellular parasites.

    They lack metabolic machinery to generate energy or to synthesise proteins, instead they rely on their host cells to carry out these functions

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  9. Asked: 3 years agoIn: Kvpy

    At which phase of the cell cycle, DNA polymerase activity is at its highest?

    (a) Gap 1 (G1)

    (b) Mitotic (M)

    (c) Synthetic (S)

    (d) Gap 2 (G2)

    76f8e
    Added an answer about 3 years ago

    Answer is : (c) Synthetic (S)DNA polymerase is an enzyme that synthesises DNA molecules from deoxyribonucleotides, the building blocks of DNA. These enzymes are essential for DNA replication. S-phase or synthetic phase is significant due to DNA synthesis. Thus, DNA polymerase activity is highest atRead more

    Answer is : (c) Synthetic (S)

    DNA polymerase is an enzyme that synthesises DNA molecules from deoxyribonucleotides, the building blocks of DNA. These enzymes are essential for DNA replication. S-phase or synthetic phase is significant due to DNA synthesis. Thus, DNA polymerase activity is highest at S-phase of cell cycle.

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  10. Asked: 3 years agoIn: Kvpy

    During meiosis, there is

    (a) one round of DNA replication and one division

    (b) two rounds of DNA replication and one division

    (c) two rounds of DNA replication and two divisions

    (d) one round of DNA replication and two divisions

    15f8c
    Added an answer about 3 years ago

    Answer is : (d) one round of DNA replication and two divisionsFor a complete meiotic cell division, there takes place one round of DNA replication during the S-phase and two divisions. This is because meiosis is a process where a single cell divides twice to produce four cells containing half the orRead more

    Answer is : (d) one round of DNA replication and two divisions

    For a complete meiotic cell division, there takes place one round of DNA replication during the S-phase and two divisions. This is because meiosis is a process where a single cell divides twice to produce four cells containing half the original amount of genetic information.

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