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integration of a=3t2-4t and a is acceleration. find distance in time 2 second
Use derivative formula for Acceleration and distance to solve this question.dv/dt = a andd2x/dt2 = a
Use derivative formula for Acceleration and distance to solve this question.
dv/dt = a and
d2x/dt2 = a
See lessavg velocity of a particle moving in a straight line , with constant acceleration a and initial velocity u in first t seconds
Total displacement S= ut + 1/2 at2Time = tAverage velocity = S/tAv velocity = u+ 1/2at
Total displacement S= ut + 1/2 at2
Time = t
Average velocity = S/t
Av velocity = u+ 1/2at
See lessTwo balls are projected simultaneously in the same vertical plane from the same point with velocities V1 and V2 with angles θ1 and θ2 respectively with the horizontal. If V1 cosθ1 = V2 cosθ2 the path of one ball as seen from the position of other ball is
1) Parabola
2) Horizontal straight line
3) Vertical straight line
4) Straight line making 45° with the vertical
Correct :-(3)Explanation :-It is given that V1 cos θ1 = V2 cos θ2 . Hence the relative velocity between them is zero. The path of one ball as seen from the position of the other ball is vertical straight line.
Correct :-(3)
Explanation :-
It is given that V1 cos θ1 = V2 cos θ2 . Hence the relative velocity between them is zero. The path of one ball as seen from the position of the other ball is vertical straight line.
See less