Find the equation of a line having a slope of -2 and passes through the intersection if 2x – y = 1 and x + 2y = 3
1. y – 2x + 1 = 0
2. y + 2x – 3 = 0
3. 2y – x – 3 = 0
4. 2y + x + 1 = 0
1. y – 2x + 1 = 0
2. y + 2x – 3 = 0
3. 2y – x – 3 = 0
4. 2y + x + 1 = 0
Correct Answer – Option 2 : y + 2x – 3 = 0
Concept:
The general equation of a line is y = mx + c
where m is the slope and c is any constant
Equation of a line with slope m and passing through (x1, y1)
(y – y1) = m (x – x1)
Equation of a line passing through (x1, y1) and (x2, y2) is:
\(\rm {y-y_1\over x-x_1}={y_2-y_1\over x_2-x_1}\)
Calculation:
Given lines are:
2x – y = 1 …(i)
x + 2y = 3 …(ii)
Adding 2 × (i) to (ii)
⇒ 5x = 5
⇒ x = 1
Putting value of x in (i)
2(1) – y = 1
⇒ y = 1
The intersection is (1, 1)
So line has the slope -2 and passes through (1, 1)
∴ Equation of the perpendicular line is
(y – y1) = m (x – x1)
⇒ y – 1 = -2 (x – 1)
⇒ y + 2x – 3 = 0