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  1. Asked: 3 years agoIn: Interest

    A worker borrowed some money on simple interest at the rate of 6% p. a. for the first 3 years, at the rate of 9% p. a. for the next 3 years, and at the rate of 14% p. a. for the period beyond 6 years. If he paid a total interest of Rs. 6,490 at the end of 7 years, how much money did he borrow?
    1. Rs. 12,500
    2. Rs. 11,000
    3. Rs. 12,000
    4. Rs. 10,000

    c63c8
    Added an answer about 3 years ago

    Correct Answer - Option 2 : Rs. 11,000Given:A worker borrowed some money on simple interest at the rate of 6% p. a. for the first 3 years, at the rate of 9% p. a. for the next 3 years, and at the rate of 14% p. a. for the period beyond 6 years. If he paid a total interest of Rs.6,490 at the end of 7Read more

    Correct Answer – Option 2 : Rs. 11,000

    Given:

    A worker borrowed some money on simple interest at the rate of 6% p. a. for the first 3 years, at the rate of 9% p. a. for the next 3 years, and at the rate of 14% p. a. for the period beyond 6 years. If he paid a total interest of Rs.6,490 at the end of 7 years.

    Concept used:

    Simple interest 

    Calculation:

    Let the principal be x = 100

    Si at the rate of 6% p. a. for 3 years 

    ⇒ 6 × 3 × x = 18x

    Si at the rate of 9% p. a. for 3 years

    ⇒ 9 × 3 × x = 27x

    Si at the rate of 14% p. a. for 1 year

    ⇒ 14 × x = 14x

    As per the question,

    ⇒ 18x + 27x + 14x = 6490

    ⇒ 59x = 6490

    ⇒ x = 110

    ∴ Principal = Rs.11000

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  2. Asked: 3 years agoIn: Interest

    Z paid Rs 10,920 after 4 years with 10% annual simple interest. How much did he borrow?

    A. Rs 7,600

    B. Rs 7,800

    C. Rs 8,200

    D. Rs 7,400


    1. A
    2. B
    3. D
    4. C

    ac5f4
    Added an answer about 3 years ago

    Correct Answer - Option 2 : BGiven:Amount = Rs. 10920Rate of interest = 10%Time = 4 yearsFormula used:SI = P × R% × Twhere, P = Principal, R = Rate of interest, T = Time Amount = P + SICalculation:Let the principal sum be Rs. P.Amount = Principal + SI⇒ 10920 = P + P × R% × T⇒ 10920 = P(1 + 10/100 ×Read more

    Correct Answer – Option 2 : B

    Given:

    Amount = Rs. 10920

    Rate of interest = 10%

    Time = 4 years

    Formula used:

    SI = P × R% × T

    where, P = Principal, R = Rate of interest, T = Time 

    Amount = P + SI

    Calculation:

    Let the principal sum be Rs. P.

    Amount = Principal + SI

    ⇒ 10920 = P + P × R% × T

    ⇒ 10920 = P(1 + 10/100 × 4)

    ⇒ 10920 = P(1 + 2/5)

    ⇒ 10920 = 7P/5

    ⇒ P = Rs. 7800

    ∴ The sum of money he borrowed is Rs. 7800.

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  3. Asked: 3 years agoIn: Interest

    Malik lent Rs. 1000 for 2 years, Rs. 1350 for 5 years , Rs. 1450 for 7 years and Rs. 1500 for 8 years at same rate of interest. He received Rs. 2472 as total simple interest, calculate rate of interest per annum.
    1. 4%
    2. 8%
    3. 6%
    4. 5%

    0b62a
    Added an answer about 3 years ago

    Correct Answer - Option 2 : 8%Given:P1 = Rs. 1000, N1 = 2 YearsP2 = Rs. 1350, N2 = 5 YearsP3 = Rs. 1450, N3 = 7 YearsP4 = Rs. 1500, N4 = 8 YearsFormula used:I = PRN / 100Where P = Principal amount, R = Rate of interest in %, N = Number of years, I = Interest earnedCalculation:Here Total Interest = (Read more

    Correct Answer – Option 2 : 8%

    Given:

    P1 = Rs. 1000, N1 = 2 Years

    P2 = Rs. 1350, N2 = 5 Years

    P3 = Rs. 1450, N3 = 7 Years

    P4 = Rs. 1500, N4 = 8 Years

    Formula used:

    I = PRN / 100

    Where P = Principal amount, R = Rate of interest in %, N = Number of years, I = Interest earned

    Calculation:

    Here Total Interest = (P1R1N1 / 100) + (P2R2N2 / 100) + (P3R3N3 / 100) + (P4R4N4 / 100)

    ⇒ (1000 × 2 × R/100) + (1350 × 5 × R / 100) + (1450 × 7 × R / 100) + (1500 × 8 × R / 100) = 2472

    ⇒ 20R + 67.5R + 101.5R + 120R = 2472

    ⇒ 309R = 2472

    ⇒ R = 8

    ∴ The interest is 8% per annum.

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  4. Asked: 3 years agoIn: Interest

    Anita borrowed two equal sums at the beginning of two successive years at 10% compound interest. At the end of the second year, she paid Rs. 12,474 to settle her debts. How much did she borrow each year?
    1. Rs. 4,800
    2. Rs. 5,000
    3. Rs. 5,400
    4. Rs. 5,600

    1b488
    Added an answer about 3 years ago

    Correct Answer - Option 3 : Rs. 5,400Given:Rate of interest = 10% At the end of second year, money paid by her = Rs. 12474 Concept used:A = P × (1 + R/100)T Where,A → Amount P → Principal R → Rate of interest T → Time Calculations:Let the principal be 100x Money after completion of first year = 100xRead more

    Correct Answer – Option 3 : Rs. 5,400

    Given:

    Rate of interest = 10% 

    At the end of second year, money paid by her = Rs. 12474 

    Concept used:

    A = P × (1 + R/100)T 

    Where,

    A → Amount 

    P → Principal 

    R → Rate of interest 

    T → Time 

    Calculations:

    Let the principal be 100x 

    Money after completion of first year = 100x × (1 + 10/100)1 

    ⇒ 100x × 110/100 = 110x 

    She borrowed the same principal in second year 

    So principal for second year = 110x + 100x = 210x 

    Money after completion of second year = 210x × (1 + 10/100)1 

    ⇒ 231x = 12474 

    ⇒ x = 54 

    Money borrowed each year =100x = 5400

    ∴ Money borrowed each year is Rs. 5400 

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  5. Asked: 3 years agoIn: Interest

    A sum of money becomes triple of itself in 10 years at the rate of simple interest, find the annual rate of interest.

    A. 5%

    B. 8%

    C. 10%

    D. 20%


    1. D
    2. B
    3. C
    4. A

    43a2e
    Added an answer about 3 years ago

    Correct Answer - Option 1 : DGiven:Time = 10 yearsMoney triple in 10 years.Formula used:Simple interest = (P × R × T)/100Where P → PrincipalT → TimeR → RateCalculation:Let the principal be 'x'.So, Amount = 3xSimple interest = 2xSimple interest = (P × R × T)/100⇒ 2x = (x × R × 10)/100⇒ R = (2 × 100)/Read more

    Correct Answer – Option 1 : D

    Given:

    Time = 10 years

    Money triple in 10 years.

    Formula used:

    Simple interest = (P × R × T)/100

    Where P → Principal

    T → Time

    R → Rate

    Calculation:

    Let the principal be ‘x’.

    So, Amount = 3x

    Simple interest = 2x

    Simple interest = (P × R × T)/100

    ⇒ 2x = (x × R × 10)/100

    ⇒ R = (2 × 100)/10

    ⇒ R = 20%

    ∴ The annual rate of interest is 20%.

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  6. Asked: 3 years agoIn: Interest

    A certain sum amounts to ₹ 756 in 2 years and to ₹ 873 is \(3\frac{1}{2}\) years at a certain rate of simple interest. The rate of interest per annum is:


    1. 11%
    2. 13%
    3. 10%
    4. 12%

    4ccb3
    Added an answer about 3 years ago

    Correct Answer - Option 2 : 13%Given:First Amount = Rs. 756Time = 2 yearsSecond Amount = Rs. 873Time = \(3\frac{1}{2}\) years = 7/2 yearsFormula Used:Simple Interest = Amount – Principal Simple Interest = (Principal × Rate × time)/100Calculation:Let the principal be 'x'. Simple Interest = Amount - PRead more

    Correct Answer – Option 2 : 13%

    Given:

    First Amount = Rs. 756

    Time = 2 years

    Second Amount = Rs. 873

    Time = \(3\frac{1}{2}\) years = 7/2 years

    Formula Used:

    Simple Interest = Amount – Principal 

    Simple Interest = (Principal × Rate × time)/100

    Calculation:

    Let the principal be ‘x’. 

    Simple Interest = Amount – Principal 

    ⇒ 756 – x

    Simple Interest = (Principal × Rate × time)/100

    Rate = (S.I × 100)/ P × t

    ⇒ Rate = ((756 – x) × 100)/ (x × 2)

    Simple Interest = Amount – Principal 

    ⇒ 873 – x

    Rate = ((873 – x) × 100)/ (x × 7/2)

    According to the Question,

    ((756 – x) × 100)/ (x × 2) = ((873 – x) × 100)/ (x × 7/2)

    ⇒ ((756 – x) × 100)/2 = 2((873 –- x) × 100)/ 7

    ⇒ 7((756 – x) × 100)= 4((873 – x) × 100)

    ⇒ 529200 – 700x = 349200 – 400x

    ⇒ 300x = 180000

    ⇒ x = 600

    Rate = ((756 – x) × 100)/ (x × 2)

    ⇒ ((756 – 600) × 100)/(600 × 2)

    ⇒ (156 × 100)/ 1200

    ⇒ 13%

    ∴ The rate of interest per annum is 13%.

     

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  7. Asked: 3 years agoIn: Interest

    There is a 60% increase in an amount in 5 years at simple interest. What will be the compound interest on Rs. 6,250 for two years at the same rate of interest, when the interest is compounded yearly?
    1. Rs. 1,500
    2. Rs. 1,590
    3. Rs. 1,560
    4. Rs 1480

    f2b37
    Added an answer about 3 years ago

    Correct Answer - Option 2 : Rs. 1,590Given:A Simple Interest on a particular sum is 60% of the principle in 5 years.Let P be the principle and R% is the rate of interest p.a.Formula Used:Simple Interest ( S.I ) = ( P× R× T )/ 100Where P = Principle, R = Rate of interest, T = time periodCompound InteRead more

    Correct Answer – Option 2 : Rs. 1,590

    Given:

    A Simple Interest on a particular sum is 60% of the principle in 5 years.

    Let P be the principle and R% is the rate of interest p.a.

    Formula Used:

    Simple Interest ( S.I ) = ( P× R× T )/ 100

    Where P = Principle, R = Rate of interest, T = time period

    Compound Interest ( C.I ) = P(1 + R/100)T – P

    Where P = Principle, R = Rate of interest, T = time period

    Calculations:

    ⇒ As from the given formula

      S.I for 5 years = 60%× P = P× R%× 5

    ⇒ R% = 60% / 5 = 12%      ____( 1 )

    As 12% = ( +3/25) = 28/25

    ⇒ C.I = 6250( 1 + 12/100 )2 – 6250

    (∵ Principle is given = Rs 6250 )

    ⇒ C.I = 6250 (28/25)2 – 6250 = 6250× 784/625 – 6250

    ( As 282 = 784, 252 = 625 )

    C.I = 7840 – 6250 = Rs 1590

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  8. Asked: 3 years agoIn: Interest

    There is 60% increase in an amount is 6 years at simple interest. What will be the compound interest of Rs. 12,000 after 3 years at the same rate ?
    1. Rs. 3575
    2. Rs. 3950
    3. Rs. 3972
    4. Rs. 3980

    50351
    Added an answer about 3 years ago

    Correct Answer - Option 3 : Rs. 3972Given Increase in salary after 6 years = 60% Formula Used A = P(1 + r/100)tsimple Interest = (principal × rate × time)/100Calculation Let the salary at 1st year be 100x Increased in salary = 60% of 100x = 60x ⇒ 60x = (100x × 6 × R)/100  ⇒ R = 10% Compound InterestRead more

    Correct Answer – Option 3 : Rs. 3972

    Given 

    Increase in salary after 6 years = 60% 

    Formula Used 

    A = P(1 + r/100)t

    simple Interest = (principal × rate × time)/100

    Calculation 

    Let the salary at 1st year be 100x 

    Increased in salary = 60% of 100x = 60x 

    ⇒ 60x = (100x × 6 × R)/100  

    ⇒ R = 10% 

    Compound Interest after 3 years = P(1 + r/100)t – P

    ⇒ 12000(1 + 10/100)3 – 12000

    ⇒ 12000 × (11/10)3 – 12000

    ⇒ 15972 – 12000 = Rs. 3972

    ∴ The required answer is Rs 3972

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  9. Asked: 3 years agoIn: Interest

    Manvendra paid Rs. 4800 as interest on a loan he took 5 years ago at 8% rate of simple interest. What was the amount he took as loan?
    1. Rs. 10800
    2. Rs. 9600
    3. Rs. 10000
    4. Rs. 12000

    7fd98
    Added an answer about 3 years ago

    Correct Answer - Option 4 : Rs. 12000GIVEN: Manvendra paid Rs. 4800 as interest on a loan he took 5 years ago at 8% rate of simple interest.FORMULA USED:Simple Interest = PRT ÷ 100Where, P = principle, R = Rate of interest, T = time periodCALCULATION:Applying the formula:4800 = (P × 8 × 5)/100⇒ P =Read more

    Correct Answer – Option 4 : Rs. 12000

    GIVEN:

    Manvendra paid Rs. 4800 as interest on a loan he took 5 years ago at 8% rate of simple interest.

    FORMULA USED:

    Simple Interest = PRT ÷ 100

    Where, P = principle, R = Rate of interest, T = time period

    CALCULATION:

    Applying the formula:

    4800 = (P × 8 × 5)/100

    ⇒ P = Rs. 12000

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  10. Asked: 3 years agoIn: Interest

    A man invests Rs. 2000 at 5% compound interest. At the end of 3 years he will get a total amount of:
    1. Rs. 2305
    2. Rs. 2316.25
    3. Rs. 2315.25
    4. Rs. 2205

    60304
    Added an answer about 3 years ago

    Correct Answer - Option 3 : Rs. 2315.25Given:Principal = Rs. 2000Rate of interest = 5%Time = 3 yearsFormula used:Amount = Principal{1 + (rate/100)}timeCalculation:Amount = Principal{1 + (rate/100)}time⇒ 2000{1 + (5/100)}3⇒ 2000(21/20)3⇒ 2000 × (9261/8000)⇒ 9261/4⇒ 2315.25∴ The amount will get afterRead more

    Correct Answer – Option 3 : Rs. 2315.25

    Given:

    Principal = Rs. 2000

    Rate of interest = 5%

    Time = 3 years

    Formula used:

    Amount = Principal{1 + (rate/100)}time

    Calculation:

    Amount = Principal{1 + (rate/100)}time

    ⇒ 2000{1 + (5/100)}3

    ⇒ 2000(21/20)3

    ⇒ 2000 × (9261/8000)

    ⇒ 9261/4

    ⇒ 2315.25

    ∴ The amount will get after 3 years is Rs. 2315.25.

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