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Navami Dixit
Navami Dixit
Asked: 3 years agoIn: Parabola

Equation of the normal at t is

tx + y = 2at + at3

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Vikrant Uppal
Vikrant Uppal
Asked: 3 years agoIn: Parabola

If the line lx + my + n = 0 touches the parabola y2 = 4ax, then

(a)   In = am

(b)  In2 = am2

(c)  l2n = am2

(d)   In = am2

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Ghalib Dasgupta
Ghalib Dasgupta
Asked: 3 years agoIn: Parabola

Equation of the hyperbola whose foci are (5,0) and (-3,0), eccentricity = 2, is
1. \(\rm {x^2\over 4}-{y^2\over 12} = 1\)
2. \(\rm {(x-1)^2\over 4}-{y^2\over 12} = 1\)
3. \(\rm {(x-1)^2\over 4}-{y^2\over 16} = 1\)
4. \(\rm {(x-1)^2\over 16}-{y^2\over 4} = 1\)

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Usman Pratap Rampersaud
Usman Pratap Rampersaud
Asked: 3 years agoIn: Parabola

In general, three normals can be drawn through a point in the plane of a parabola to the curve.

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Mona Dhanush Ram
Mona Dhanush Ram
Asked: 3 years agoIn: Parabola

Let L be the point (t, 2) and M be a point on the y-axis such that the slope of LM is −t. Then, the locus of the midpoint of LM is a parabola whose latus rectum is

(a)  2

(b)   1/2

(c)   4

(d)  1/4

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Runjhun Siddharth Swaminathan
Runjhun Siddharth Swaminathan
Asked: 3 years agoIn: Parabola

Show that the locus of the midpoints of chords of a parabola passing through the vertex is in turn a parabola whose latus rectum is half of the latus rectum of the original. 

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Amrita Anthony
Amrita Anthony
Asked: 3 years agoIn: Parabola

Show that the chords of contacts of points on the line 2x – 3y + 4 = 0 with respect to the parabola y2 = 4ax pass through a fixed point.

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Lalit Padmanabhan
Lalit Padmanabhan
Asked: 3 years agoIn: Parabola

A point P of the parabola y2 = 4ax lies on the line y = x. The normal chord PQ, normal at P, subtends an angle at the focus of the parabola which equal

(A)  60º

(B)  45º

(C) 30º

(D)  90º

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Naseer Lal Ganesh
Naseer Lal Ganesh
Asked: 3 years agoIn: Parabola

The foci of a hyperbola coincide with the foci of the ellipse \(\rm \frac{x^2}{25}+\frac{y^2}{16}=1\), find the equation of the hyperbola if its eccentricity is 3.


1. \(\rm \frac{x^2}{1}-\frac{y^2}{8}=1\)
2. \(\rm \frac{x^2}{8}-\frac{y^2}{1}=1\)
3. \(\rm \frac{x^2}{9}-\frac{y^2}{16}=1\)
4. \(\rm \frac{x^2}{25}-\frac{y^2}{16}=1\)

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Azhar Chandra
Azhar Chandra
Asked: 3 years agoIn: Parabola

The orthocentre of a triangle formed by three tangents to a parabola y2 = 8x lies on

(a)  x + 1 = 0

(b)  x + 2 = 0

(c)  x + = 0

(d)  x – 1 = 0

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