While numerically solving the differential equation \(\frac{{dy}}{{dx}} + 2x{y^2} = 0,y\left( 0 \right) = 1\) using Euler’s predictor corrector (improved Euler-Cauchy) with a step size of 0.2, the value of y after the first step is

While numerically solving the differential equation \(\frac{{dy}}{{dx}

1.	While numerically solving the differential equation \(\frac{{dy}}{{dx}} + 2x{y^2} = 0,y\left( 0 \right) = 1\) using Euler’s predictor corrector (improved Euler-Cauchy) with a step size of 0.2, the value of y after the first step is
A.	1
B.	1.03
C.	0.97
D.	0.96
Answer» E.