Which one of the following is the general solution of the first order differential equation$\frac{{dy}}{{dx}} = {\left( {x + y - 1} \right)^2}$, where x, y are real?

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

y = 1 + x + tan–1 (x + c), where c is a constant.

TuteeHUB · Answer

y = 1 + x + tan(x + c), where c is a constant.

TuteeHUB · Answer

y = 1 – x + tan–1 (x + c), where c is a constant.

TuteeHUB · Answer

y = 1 – x + tan(x + c), where c is a constant.

1.	Which one of the following is the general solution of the first order differential equation\(\frac{{dy}}{{dx}} = {\left( {x + y - 1} \right)^2}\), where x, y are real?
A.	y = 1 + x + tan–1 (x + c), where c is a constant.
B.	y = 1 + x + tan(x + c), where c is a constant.
C.	y = 1 – x + tan–1 (x + c), where c is a constant.
D.	y = 1 – x + tan(x + c), where c is a constant.
Answer» E.

Which one of the following is the general solution of the first order differential equation\(\frac{{dy}}{{dx}} = {\left( {x + y - 1} \right)^2}\), where x, y are real?

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