1.

Which one of the following does NOT equal \(\left| {\begin{array}{*{20}{c}}1&x&{{x^2}}\\1&y&{{y^2}}\\1&z&{{z^2}}\end{array}} \right|\)?

A. \(\left| {\begin{array}{*{20}{c}}1&{x\left( {x + 1} \right)}&{x + 1}\\1&{y\left( {y + 1} \right)}&{y + 1}\\1&{z\left( {z + 1} \right)}&{z + 1}\end{array}} \right|\)
B. \(\left| {\begin{array}{*{20}{c}}1&{x + 1}&{{x^2} + 1}\\1&{y + 1}&{{y^2} + 1}\\1&{z + 1}&{{z^2} + 1}\end{array}} \right|\)
C. \(\left| {\begin{array}{*{20}{c}}0&{x - y}&{{x^2} - {y^2}}\\0&{y - z}&{{y^2} - {z^2}}\\1&z&{{z^2}}\end{array}} \right|\)
D. \(\left| {\begin{array}{*{20}{c}}2&{x + y}&{{x^2} + {y^2}}\\2&{y + z}&{{y^2} + {z^2}}\\1&z&{{z^2}}\end{array}} \right|\)
Answer» B. \(\left| {\begin{array}{*{20}{c}}1&{x + 1}&{{x^2} + 1}\\1&{y + 1}&{{y^2} + 1}\\1&{z + 1}&{{z^2} + 1}\end{array}} \right|\)


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