

MCQOPTIONS
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1. |
Which of these is the vibrational rate equation? |
A. | \(\frac {de_{vib}}{dt} = \frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib)b) τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\) c) evib = τ(e\(_{vib}^{eq}\) – evib)d) \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evi |
B. | τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\) |
C. | evib = τ(e\(_{vib}^{eq}\) – evib) |
D. | \(\frac {de_{vib}}{dt}\) = \(\frac {1}{τ}\)(e\(_{vib}^{eq}\) – evib) |
Answer» B. τ = \(\frac {1}{k_{1, 0} (1 – e^{- hv/kT} )}\) | |