Which of the following is the correct expression for h(n) in terms of H(k+α)?

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

$\frac{1}{M} \sum_{k=0}^{M-1}H(k+α)e^{j2π(k+α)n/M}$; n=0,1,2…M-1

TuteeHUB · Answer

$\sum_{k=0}^{M-1}H(k+α)e^{j2π(k+α)n/M}$; n=0,1,2…M-1

TuteeHUB · Answer

$\frac{1}{M} \sum_{k=0}^{M+1}H(k+α)e^{j2π(k+α)n/M}$; n=0,1,2…M+1

TuteeHUB · Answer

$\sum_{k=0}^{M+1}H(k+α)e^{j2π(k+α)n/M}$; n=0,1,2…M+1

1.	Which of the following is the correct expression for h(n) in terms of H(k+α)?
A.	\(\frac{1}{M} \sum_{k=0}^{M-1}H(k+α)e^{j2π(k+α)n/M}\); n=0,1,2…M-1
B.	\(\sum_{k=0}^{M-1}H(k+α)e^{j2π(k+α)n/M}\); n=0,1,2…M-1
C.	\(\frac{1}{M} \sum_{k=0}^{M+1}H(k+α)e^{j2π(k+α)n/M}\); n=0,1,2…M+1
D.	\(\sum_{k=0}^{M+1}H(k+α)e^{j2π(k+α)n/M}\); n=0,1,2…M+1
Answer» B.

Discussion