Which expression suits best when the solid angle obtained by the noise source is less than antenna solid angle?

PA ΩB=PB ΩA and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)

PA ΩA=PB ΩB and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)

PA ΩB=PB ΩA and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)

ΔTA=\(\frac{\Omega_A}{\Omega_B} T_B\) and PA ΩB=PB ΩA

ΔTA=\(\frac{\Omega_A}{\Omega_B} T_B\) and PA ΩA=PB ΩB

Which expression suits best when the solid angle obtained by the nois

1.	Which expression suits best when the solid angle obtained by the noise source is less than antenna solid angle?
A.	PA ΩA=PB ΩB and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)
B.	PA ΩB=PB ΩA and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)
C.	ΔTA=\(\frac{\Omega_A}{\Omega_B} T_B\) and PA ΩB=PB ΩA
D.	ΔTA=\(\frac{\Omega_A}{\Omega_B} T_B\) and PA ΩA=PB ΩB
Answer» B. PA ΩB=PB ΩA and ΔTA=\(\frac{\Omega_B}{\Omega_A} T_B\)