When a thin cylinder of diameter ‘d’ & thickess ‘t’ is pressurized with an internal pressure of 'p' (1/m is the poison’s ratio & E is the modulus of elasticity), then

• A. The circumferential strain will be equal. to \(\frac{{pd}}{{2tE}}\left[ {\left( {\frac{1}{2}} \right) - \left( {\frac{1}{m}} \right)} \right]\)
• B. The Longitudinal strain will be equal to \(\frac{{pd}}{{2tE}}\left[ {1 - \frac{1}{{2m}}} \right]\)
• C. The Longitudinal stress will be equal to pd/2t
• D. The ratio of the longitudinal strain to circumferential strain will be equal to (m-2)/(2m-1)