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| 1. |
When a liquid drop is in contact with a solid surface, the contact angle at equilibrium is given by ______ |
| A. | cosθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) |
| B. | sinθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) |
| C. | cosθ=\(\frac{\gamma_{SL}-\gamma_{GS}}{\gamma_{LG}}\) |
| D. | cosθ=\(\frac{\gamma_{LG}-\gamma_{SL}}{\gamma_{GS}}\) |
| Answer» B. sinθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) | |