

MCQOPTIONS
Saved Bookmarks
1. |
When a liquid drop is in contact with a solid surface, the contact angle at equilibrium is given by ______ |
A. | cosθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) |
B. | sinθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) |
C. | cosθ=\(\frac{\gamma_{SL}-\gamma_{GS}}{\gamma_{LG}}\) |
D. | cosθ=\(\frac{\gamma_{LG}-\gamma_{SL}}{\gamma_{GS}}\) |
Answer» B. sinθ=\(\frac{\gamma_{GS}-\gamma_{SL}}{\gamma_{LG}}\) | |