What is the value of the limit f(x) = \(\frac{sin^2⁡x+\sqrt 2 sin ⁡x}{x^2-4x}\) if x approaches 0?

What is the value of the limit f(x) = \(\frac{sin^2⁡x+\sqrt 2 sin �

1.	What is the value of the limit f(x) = \(\frac{sin^2⁡x+\sqrt 2 sin ⁡x}{x^2-4x}\) if x approaches 0?
A.	\(\frac{1}{\sqrt 2}\)
B.	\(\frac{-1}{\sqrt 2}\)
C.	\(\frac{-1}{2\sqrt 2}\)
D.	\(\frac{1}{2\sqrt 2}\)
Answer» D.

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