1.

What is the total number of atoms present in 25.0 mg of camphor, \[{{C}_{10}}{{H}_{16}}O\] ?

A. \[~\text{9}.\text{89 }\times \text{ 1}{{0}^{\text{19}}}\]                
B.  \[\text{2}.\text{67 }\times \text{ 1}{{0}^{\text{21}}}\]  
C. \[\text{6}.0\text{2 }\times \text{ 1}{{0}^{\text{2}0}}\]                  
D.  \[\text{2}.\text{57 }\times \text{ 1}{{0}^{\text{21}}}\]
Answer» C. \[\text{6}.0\text{2 }\times \text{ 1}{{0}^{\text{2}0}}\]                  


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