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1. |
What is the total number of atoms present in 25.0 mg of camphor, \[{{C}_{10}}{{H}_{16}}O\] ? |
A. | \[~\text{9}.\text{89 }\times \text{ 1}{{0}^{\text{19}}}\] |
B. | \[\text{2}.\text{67 }\times \text{ 1}{{0}^{\text{21}}}\] |
C. | \[\text{6}.0\text{2 }\times \text{ 1}{{0}^{\text{2}0}}\] |
D. | \[\text{2}.\text{57 }\times \text{ 1}{{0}^{\text{21}}}\] |
Answer» C. \[\text{6}.0\text{2 }\times \text{ 1}{{0}^{\text{2}0}}\] | |