1.

What is the Taylor series expansion of f(x)= x2-x+1 about the point x=-1?

A. f(x) = -3-3(x+1)+(x+1)<sup>2</sup>
B. f(x) = -3-(x+1)+(x+1)<sup>2</sup>
C. f(x) = -3-3(x+1)+2(x+1)<sup>2</sup>
D. f(x) = -1-3(x+1)+2(x+1)<sup>2</sup>
Answer» B. f(x) = -3-(x+1)+(x+1)<sup>2</sup>


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