What is the sum of n terms of the series $\sqrt 2 + \sqrt 8 + \sqrt {18} + \sqrt {32} + \ldots ?$

Question

TuteeHUB · Accepted Answer

$\frac{{{\rm{n}}\left( {{\rm{n}} - 1} \right)}}{2}$

TuteeHUB · Answer

$\frac{{{\rm{n}}\left( {{\rm{n}} - 1} \right)}}{{\sqrt 2 }}$

TuteeHUB · Answer

$\sqrt 2 {\rm{n}}\left( {{\rm{n}} + 1} \right)$

TuteeHUB · Answer

$\frac{{{\rm{n}}\left( {{\rm{n}} + 1} \right)}}{{\sqrt 2 }}$

1.	What is the sum of n terms of the series \(\sqrt 2 + \sqrt 8 + \sqrt {18} + \sqrt {32} + \ldots ?\)
A.	\(\frac{{{\rm{n}}\left( {{\rm{n}} - 1} \right)}}{{\sqrt 2 }}\)
B.	\(\sqrt 2 {\rm{n}}\left( {{\rm{n}} + 1} \right)\)
C.	\(\frac{{{\rm{n}}\left( {{\rm{n}} + 1} \right)}}{{\sqrt 2 }}\)
D.	\(\frac{{{\rm{n}}\left( {{\rm{n}} - 1} \right)}}{2}\)
Answer» D. \(\frac{{{\rm{n}}\left( {{\rm{n}} - 1} \right)}}{2}\)

What is the sum of n terms of the series \(\sqrt 2 + \sqrt 8 + \sqrt {18} + \sqrt {32} + \ldots ?\)