What is the reason behind the non-existence of any real function which satisfies the differential equation, (y’)2 + 1 = 0?

Question

TuteeHUB · Accepted Answer

Because for any real function, the left-hand side of the equation becomes infinity

TuteeHUB · Answer

Because for any real function, the left-hand side of the equation will be less than, or equal to one and thus cannot be zero

TuteeHUB · Answer

Because for any real function, the left-hand side of the equation becomes zero

TuteeHUB · Answer

Because for any real function, the left-hand side of the equation will be greater than, or equal to one and thus cannot be zero

TuteeHUB · Answer

Because for any real function, the left-hand side of the equation becomes infinity

1.	What is the reason behind the non-existence of any real function which satisfies the differential equation, (y’)2 + 1 = 0?
A.	Because for any real function, the left-hand side of the equation will be less than, or equal to one and thus cannot be zero
B.	Because for any real function, the left-hand side of the equation becomes zero
C.	Because for any real function, the left-hand side of the equation will be greater than, or equal to one and thus cannot be zero
D.	Because for any real function, the left-hand side of the equation becomes infinity
Answer» D. Because for any real function, the left-hand side of the equation becomes infinity

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