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| 1. |
What is the order N of the low pass Butterworth filter in terms of KP and KS? |
| A. | ( frac{log u2061[(10^ frac{K_P}{10}-1)/(10^ frac{K_s}{10}-1)]}{2 log u2061( frac{ Omega_P}{ Omega_S})} ) |
| B. | ( frac{log u2061[(10^ frac{K_P}{10}+1)/(10^ frac{K_s}{10}+1)]}{2 log u2061( frac{ Omega_P}{ Omega_S})} ) |
| C. | ( frac{log u2061[(10^ frac{-K_P}{10}+1)/(10^ frac{-K_s}{10}+1)]}{2 log u2061( frac{ Omega_P}{ Omega_S})} ) |
| D. | ( frac{log u2061[(10^ frac{-K_P}{10}-1)/(10^ frac{-K_s}{10}-1)]}{2 log u2061( frac{ Omega_P}{ Omega_S})} ) |
| Answer» E. | |