1.

What is the new capacitance of the plates, when a slab of Dielectric Constant K and thickness one-fourth of the separation of plate is inserted between the plates?

A. 4KC<sub>o</sub>/K + 2
B. 4KC<sub>o</sub>/1 + 2K
C. 4KC<sub>o</sub>/K + 3
D. 4KC<sub>o</sub>/1 + 3K
Answer» E.


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