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1. |
What is the new capacitance of the plates, when a slab of Dielectric Constant K and thickness one-fourth of the separation of plate is inserted between the plates? |
A. | 4KC<sub>o</sub>/K + 2 |
B. | 4KC<sub>o</sub>/1 + 2K |
C. | 4KC<sub>o</sub>/K + 3 |
D. | 4KC<sub>o</sub>/1 + 3K |
Answer» E. | |