

MCQOPTIONS
Saved Bookmarks
1. |
What is the lattice constant for FCC crystal having atomic radius 1.476 ‚Äö√†√∂‚àö√?# |
A. | 1.476 √Ö |
B. | 4.1748 √Ö |
C. | 5.216 √Ö |
D. | 0 |
Answer» C. 5.216 ‚Äö√†√∂‚àö√± | |