What is the formula to compute net rate change of the population of the ith level?

Question

TuteeHUB · Accepted Answer

( frac {dN_i}{dt} ) = P_{i + 1, i} ZN_{i + 1} + P_{i 1, i} ZN_{i 1} + P_{i, i + 1} ZN_i + P_{i, i 1} ZN_i

TuteeHUB · Answer

(  frac {dN_i}{dt}  ) = Pi + 1, i ZNi + 1 + Pi   1, i ZNi   1   Pi, i + 1 ZNi   Pi, i   1 ZNi

TuteeHUB · Answer

(  frac {dN_i}{dt}  ) =   Pi + 1, i ZNi + 1 + Pi   1, i ZNi   1 + Pi, i + 1 ZNi + Pi, i   1 ZNi

TuteeHUB · Answer

(  frac {dN_i}{dt}  ) = Pi + 1, i ZNi + 1   Pi, i + 1 ZNi

TuteeHUB · Answer

(  frac {dN_i}{dt}  ) = + Pi   1, i ZNi   1   Pi, i   1 ZNi

1.	What is the formula to compute net rate change of the population of the i^th level?
A.	( frac {dN_i}{dt} ) = P<sub>i + 1, i</sub> ZN<sub>i + 1</sub> + P<sub>i 1, i</sub> ZN<sub>i 1</sub> P<sub>i, i + 1</sub> ZN<sub>i</sub> P<sub>i, i 1</sub> ZN<sub>i</sub>
B.	( frac {dN_i}{dt} ) = P<sub>i + 1, i</sub> ZN<sub>i + 1</sub> + P<sub>i 1, i</sub> ZN<sub>i 1</sub> + P<sub>i, i + 1</sub> ZN<sub>i</sub> + P<sub>i, i 1</sub> ZN<sub>i</sub>
C.	( frac {dN_i}{dt} ) = P<sub>i + 1, i</sub> ZN<sub>i + 1</sub> P<sub>i, i + 1</sub> ZN<sub>i</sub>
D.	( frac {dN_i}{dt} ) = + P<sub>i 1, i</sub> ZN<sub>i 1</sub> P<sub>i, i 1</sub> ZN<sub>i</sub>
Answer» B. ( frac {dN_i}{dt} ) = P<sub>i + 1, i</sub> ZN<sub>i + 1</sub> + P<sub>i 1, i</sub> ZN<sub>i 1</sub> + P<sub>i, i + 1</sub> ZN<sub>i</sub> + P<sub>i, i 1</sub> ZN<sub>i</sub>

What is the formula to compute net rate change of the population of the i^th level?