What is the following code segment doing? void fn( ){ char c; cin.get(c); if (c != ‘
’) { fn( ); cout.put(c); } }

Question

TuteeHUB · Accepted Answer

It will go in an infinite loop.

TuteeHUB · Answer

The string entered is printed as it is.

TuteeHUB · Answer

The string entered is printed in reverse order.

TuteeHUB · Answer

It will print an empty line.

1.	What is the following code segment doing? void fn( ){ char c; cin.get(c); if (c != ‘\n’) { fn( ); cout.put(c); } }
A.	The string entered is printed as it is.
B.	The string entered is printed in reverse order.
C.	It will go in an infinite loop.
D.	It will print an empty line.
Answer» C. It will go in an infinite loop.

What is the following code segment doing? void fn( ){ char c; cin.get(c); if (c != ‘\n’) { fn( ); cout.put(c); } }