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				| 1. | What is the final result obtained by substituting Fc=kB-B/2, T= 1/2B and say n = 2m i.e., for even and n=2m-1 for odd in equation x(nT)= (u_c (nT)cos 2 F_c nT-u_s (nT)sin 2 F_c nT )? | 
| A. | ((-1)^m u_c (mT_1)-u_s ) | 
| B. | (u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} ) | 
| C. | None | 
| D. | ((-1)^m u_c (mT_1)- u_s (mT_1- frac{T_1}{2})(-1)^{m+k+1} ) | 
| Answer» E. | |