 
			 
			MCQOPTIONS
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				| 1. | What is the expression for heat transfer coefficient for a horizontally placed condenser? | 
| A. | hHOR=0.943\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) | 
| B. | hHOR=0.743\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) | 
| C. | hHOR=0.723\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) | 
| D. | hHOR=0.725\([\frac{K^3 p^2 g h_{fg}}{μx(T_{sat} – T_L)}]^{0.25}\) | 
| Answer» E. | |