What is the derivative of \(\frac{3x^2}{(1-sinx)}\)? – McqOptions

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1.	What is the derivative of \(\frac{3x^2}{(1-sinx)}\)?
A.	\(\frac{6xsinx-3x^2 cosx}{(1-sinx)^2} \)
B.	\(\frac{6x}{1-sinx} \)
C.	\(\frac{6xsinx-3x^2 cosx-6x}{(1-sinx)^2} \)
D.	\(\frac{6xsinx-3cosx-6}{(1-sinx)^2} \)
Answer» D. \(\frac{6xsinx-3cosx-6}{(1-sinx)^2} \)

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