What is the correct Entity X in the equivalent diameter of a Triangular pitch?

Question

TuteeHUB · Accepted Answer

NA

TuteeHUB · Answer

D = $\frac{4(\frac{X}{2}Pt^2-\frac{\frac{1}{2}πOD^2}{4})}{\frac{1}{2}πOD}$

TuteeHUB · Answer

0.23

TuteeHUB · Answer

0.027

TuteeHUB · Answer

0.86

TuteeHUB · Answer

0.086

1.	What is the correct Entity X in the equivalent diameter of a Triangular pitch?
A.	D = \(\frac{4(\frac{X}{2}Pt^2-\frac{\frac{1}{2}πOD^2}{4})}{\frac{1}{2}πOD}\)
B.	0.23
C.	0.027
D.	0.86
E.	0.086
Answer» D.

Discussion