What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac

1.	What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
A.	x=±3
B.	y=±3
C.	x=±2
D.	y=±2
Answer» B.

Discussion

If foci of an ellipse are (0, ±3) and length of semimajor axis is 5 units, then find the equation of ellipse.
What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is length of latus rectum for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is minor axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is major axis length for ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
What is eccentricity for \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?
Find the coordinates of foci of ellipse \((\frac{x}{16})^2+(\frac{y}{25})^2\)=1.
Find the coordinates of foci of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1.