Using mathematical induction, the numbers \[{{a}_{n}}'s\]are defined by \[{{a}_{0}}=1,\,\,{{a}_{n+1}}=3{{n}^{2}}+n+{{a}_{n'}}\] \[(n\ge 0).\]Then, \[{{a}_{n}}\] is equal to

Using mathematical induction, the numbers \[{{a}_{n}}'s\]are defined b

1.	Using mathematical induction, the numbers \[{{a}_{n}}'s\]are defined by \[{{a}_{0}}=1,\,\,{{a}_{n+1}}=3{{n}^{2}}+n+{{a}_{n'}}\] \[(n\ge 0).\]Then, \[{{a}_{n}}\] is equal to
A.	\[{{n}^{3}}+{{n}^{2}}+1\]
B.	\[{{n}^{3}}-{{n}^{2}}+1\]
C.	\[{{n}^{3}}-{{n}^{2}}\]
D.	\[{{n}^{3}}+{{n}^{2}}\]
Answer» C. \[{{n}^{3}}-{{n}^{2}}\]

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Using mathematical induction, the numbers \[{{a}_{n}}'s\]are defined by \[{{a}_{0}}=1,\,\,{{a}_{n+1}}=3{{n}^{2}}+n+{{a}_{n'}}\] \[(n\ge 0).\]Then, \[{{a}_{n}}\] is equal to

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