Two given circles \[{{x}^{2}}+{{y}^{2}}+ax+by+c=0\]and \[{{x}^{2}}+{{y}^{2}}+dx+ey+f=0\]will intersect each other orthogonally, only when

Two given circles \[{{x}^{2}}+{{y}^{2}}+ax+by+c=0\]and \[{{x}^{2}}+{{y

1.	Two given circles \[{{x}^{2}}+{{y}^{2}}+ax+by+c=0\]and \[{{x}^{2}}+{{y}^{2}}+dx+ey+f=0\]will intersect each other orthogonally, only when
A.	\[a+b+c=d+e+f\]
B.	\[ad+be=c+f\]
C.	\[ad+be=2c+2f\]
D.	\[2ad+2be=c+f\]
Answer» D. \[2ad+2be=c+f\]

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Two given circles \[{{x}^{2}}+{{y}^{2}}+ax+by+c=0\]and \[{{x}^{2}}+{{y}^{2}}+dx+ey+f=0\]will intersect each other orthogonally, only when

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