Two circles of radius R and r, where the circle with radius r having a fixed point roll inside the circle with radius R along its circumference forming epicycloid. What is the equation of hypocycloid in X(θ)?

X(θ) = (R+r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)

X(θ) = (R-r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)

X(θ) = (R+r)cos(θ)+rcos(\(\frac{R+r}{r}\) θ)

X(θ) = (R-r)cos(θ)+rcos(\(\frac{R-r}{r}\) θ)

X(θ) = (R+r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)

Two circles of radius R and r, where the circle with radius r having

1.	Two circles of radius R and r, where the circle with radius r having a fixed point roll inside the circle with radius R along its circumference forming epicycloid. What is the equation of hypocycloid in X(θ)?
A.	X(θ) = (R-r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)
B.	X(θ) = (R+r)cos(θ)+rcos(\(\frac{R+r}{r}\) θ)
C.	X(θ) = (R-r)cos(θ)+rcos(\(\frac{R-r}{r}\) θ)
D.	X(θ) = (R+r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)
Answer» D. X(θ) = (R+r)cos(θ)-rcos(\(\frac{R-r}{r}\) θ)

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Two circles of radius R and r, where the circle with radius r having a fixed point roll inside the circle with radius R along its circumference forming epicycloid. What is the equation of hypocycloid in X(θ)?

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