Two chords AB and CD of a circle intersect at a point P outside the circle. If ∠PAC = 50° , then ∠PDB is equal to

Two chords AB and CD of a circle intersect at a point P outside the ci

1.	Two chords AB and CD of a circle intersect at a point P outside the circle. If ∠PAC = 50° , then ∠PDB is equal to
A.	90°
B.	130°
C.	50°
D.	None of the above
Answer» D. None of the above