To find the root of f(x) = 0 by using the bisection method, an iteration is begun with the lower and upper guesses of the root. If xlower and xupper are the roots, then at the end of the iteration, the absolute relative approximate error in the estimated value of the root would be

Question

TuteeHUB · Accepted Answer

$\left| {\frac{{{x_{upper}}\; + \;{x_{lower}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right|$

TuteeHUB · Answer

$\left| {\frac{{{x_{upper}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right|$

TuteeHUB · Answer

$\left| {\frac{{{x_{lower}}}}{{{x_{upper\;}} + \;{x_{lower}}}}} \right|$

TuteeHUB · Answer

$\left| {\frac{{{x_{upper\;}} - \;{x_{lower}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right|$

1.	To find the root of f(x) = 0 by using the bisection method, an iteration is begun with the lower and upper guesses of the root. If xlower and xupper are the roots, then at the end of the iteration, the absolute relative approximate error in the estimated value of the root would be
A.	\(\left\| {\frac{{{x_{upper}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right\|\)
B.	\(\left\| {\frac{{{x_{lower}}}}{{{x_{upper\;}} + \;{x_{lower}}}}} \right\|\)
C.	\(\left\| {\frac{{{x_{upper\;}} - \;{x_{lower}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right\|\)
D.	\(\left\| {\frac{{{x_{upper}}\; + \;{x_{lower}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right\|\)
Answer» D. \(\left\| {\frac{{{x_{upper}}\; + \;{x_{lower}}}}{{{x_{upper}}\; + \;{x_{lower}}}}} \right\|\)

To find the root of f(x) = 0 by using the bisection method, an iteration is begun with the lower and upper guesses of the root. If xlower and xupper are the roots, then at the end of the iteration, the absolute relative approximate error in the estimated value of the root would be

Discussion

No Comment Found

Related MCQs

Reply to Comment