MCQOPTIONS
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| 1. |
Three identical impedances, each of (9.8 + j10) Ω, are connected across a 400 V, 50 Hz AC supply. The power supplied to the load is measured by the two-wattmeter method.Find the readings of the two wattmeters if the impedances are connected in star. |
| A. | W1 = 6.36 kW and W2 = 1.64 kW |
| B. | W1 = -4.4 kW and W2 = 1 kW |
| C. | W1 = -6.36 kW and W2 = 1.64 kW |
| D. | W1 = 1 kW and W2 = 4.4 kW |
| Answer» B. W1 = -4.4 kW and W2 = 1 kW | |