1.

Three identical impedances, each of (9.8 + j10) Ω, are connected across a 400 V, 50 Hz AC supply. The power supplied to the load is measured by the two-wattmeter method.Find the readings of the two wattmeters if the impedances are connected in star.

A. W1 = 6.36 kW and W2 = 1.64 kW
B. W1 = -4.4 kW and W2 = 1 kW
C. W1 = -6.36 kW and W2 = 1.64 kW
D. W1 = 1 kW and W2 = 4.4 kW
Answer» B. W1 = -4.4 kW and W2 = 1 kW


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