Thermal runaway in BJT will take place if the quiescent point is such that

Question

TuteeHUB · Accepted Answer

${{\rm{V}}_{{\rm{CE}}}} = {{\rm{V}}_{{\rm{CC}}}}$

TuteeHUB · Answer

${{\rm{V}}_{{\rm{CE}}}} > \frac{1}{2}{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}$

TuteeHUB · Answer

${{\rm{V}}_{{\rm{CE}}}} < 2{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}$

TuteeHUB · Answer

${{\rm{V}}_{{\rm{CE}}}} < \frac{1}{2}{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}$

1.	Thermal runaway in BJT will take place if the quiescent point is such that
A.	\({{\rm{V}}_{{\rm{CE}}}} > \frac{1}{2}{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}\)
B.	\({{\rm{V}}_{{\rm{CE}}}} = {{\rm{V}}_{{\rm{CC}}}}\)
C.	\({{\rm{V}}_{{\rm{CE}}}} < 2{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}\)
D.	\({{\rm{V}}_{{\rm{CE}}}} < \frac{1}{2}{\rm{\;}}{{\rm{V}}_{{\rm{CC}}}}\)
Answer» B. \({{\rm{V}}_{{\rm{CE}}}} = {{\rm{V}}_{{\rm{CC}}}}\)

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