The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.

Question

The variation of interatomic energy with atomic distance is given by the following equation                           V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.

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NA

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Find the value of energy at the point where the interatomic force is zero?

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– ε

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ε

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σ

1.	The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.
A.	Find the value of energy at the point where the interatomic force is zero?
B.	– ε
C.	ε
D.	0
E.	σ
Answer» B.

The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.

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