1.

The variation of interatomic energy with atomic distance is given by the following equation V(r)=4ε[(σ/r12)−(σ/r6)]Where V(r) is the potential energy, and r is interatomic distance. ε and σ are constant.Find the value of energy at the point where the interatomic force is zero?

A. – ε
B. ε
C. 0
D. σ
Answer» B. ε


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