The value of \({\rm{co}}{{\rm{t}}^2}{\rm{A\;}} - \frac{1}{{{{\sin }^2}A}}\) is equal to∶

The value of \({\rm{co}}{{\rm{t}}^2}{\rm{A\;}} - \frac{1}{{{{\sin }^2}

1.	The value of \({\rm{co}}{{\rm{t}}^2}{\rm{A\;}} - \frac{1}{{{{\sin }^2}A}}\) is equal to∶
A.	0
B.	-1
C.	-2
D.	1
Answer» C. -2