The value of \(\frac{1}{{{{\log }_3}e}} + \frac{1}{{{{\log }_3}{e^2}}} + \frac{1}{{{{\log }_3}{e^4}}} + \ldots \) up to infinite terms is

The value of \(\frac{1}{{{{\log }_3}e}} + \frac{1}{{{{\log }_3}{e^2}}}

1.	The value of \(\frac{1}{{{{\log }_3}e}} + \frac{1}{{{{\log }_3}{e^2}}} + \frac{1}{{{{\log }_3}{e^4}}} + \ldots \) up to infinite terms is
A.	loge 9
B.	0
C.	1
D.	loge 3
Answer» B. 0